- FindStat

Identifier

St000143: Integer partitions ⟶ ℤ

Values

=>
                            Cc0002;cc-rep
                            
                            
                            

                        []=>0
[1]=>0
[2]=>0
[1,1]=>1
[3]=>0
[2,1]=>0
[1,1,1]=>1
[4]=>0
[3,1]=>0
[2,2]=>2
[2,1,1]=>1
[1,1,1,1]=>1
[5]=>0
[4,1]=>0
[3,2]=>0
[3,1,1]=>1
[2,2,1]=>2
[2,1,1,1]=>1
[1,1,1,1,1]=>1
[6]=>0
[5,1]=>0
[4,2]=>0
[4,1,1]=>1
[3,3]=>3
[3,2,1]=>0
[3,1,1,1]=>1
[2,2,2]=>2
[2,2,1,1]=>2
[2,1,1,1,1]=>1
[1,1,1,1,1,1]=>1
[7]=>0
[6,1]=>0
[5,2]=>0
[5,1,1]=>1
[4,3]=>0
[4,2,1]=>0
[4,1,1,1]=>1
[3,3,1]=>3
[3,2,2]=>2
[3,2,1,1]=>1
[3,1,1,1,1]=>1
[2,2,2,1]=>2
[2,2,1,1,1]=>2
[2,1,1,1,1,1]=>1
[1,1,1,1,1,1,1]=>1
[8]=>0
[7,1]=>0
[6,2]=>0
[6,1,1]=>1
[5,3]=>0
[5,2,1]=>0
[5,1,1,1]=>1
[4,4]=>4
[4,3,1]=>0
[4,2,2]=>2
[4,2,1,1]=>1
[4,1,1,1,1]=>1
[3,3,2]=>3
[3,3,1,1]=>3
[3,2,2,1]=>2
[3,2,1,1,1]=>1
[3,1,1,1,1,1]=>1
[2,2,2,2]=>2
[2,2,2,1,1]=>2
[2,2,1,1,1,1]=>2
[2,1,1,1,1,1,1]=>1
[1,1,1,1,1,1,1,1]=>1
[9]=>0
[8,1]=>0
[7,2]=>0
[7,1,1]=>1
[6,3]=>0
[6,2,1]=>0
[6,1,1,1]=>1
[5,4]=>0
[5,3,1]=>0
[5,2,2]=>2
[5,2,1,1]=>1
[5,1,1,1,1]=>1
[4,4,1]=>4
[4,3,2]=>0
[4,3,1,1]=>1
[4,2,2,1]=>2
[4,2,1,1,1]=>1
[4,1,1,1,1,1]=>1
[3,3,3]=>3
[3,3,2,1]=>3
[3,3,1,1,1]=>3
[3,2,2,2]=>2
[3,2,2,1,1]=>2
[3,2,1,1,1,1]=>1
[3,1,1,1,1,1,1]=>1
[2,2,2,2,1]=>2
[2,2,2,1,1,1]=>2
[2,2,1,1,1,1,1]=>2
[2,1,1,1,1,1,1,1]=>1
[1,1,1,1,1,1,1,1,1]=>1
[10]=>0
[9,1]=>0
[8,2]=>0
[8,1,1]=>1
[7,3]=>0
[7,2,1]=>0
[7,1,1,1]=>1
[6,4]=>0
[6,3,1]=>0
[6,2,2]=>2
[6,2,1,1]=>1
[6,1,1,1,1]=>1
[5,5]=>5
[5,4,1]=>0
[5,3,2]=>0
[5,3,1,1]=>1
[5,2,2,1]=>2
[5,2,1,1,1]=>1
[5,1,1,1,1,1]=>1
[4,4,2]=>4
[4,4,1,1]=>4
[4,3,3]=>3
[4,3,2,1]=>0
[4,3,1,1,1]=>1
[4,2,2,2]=>2
[4,2,2,1,1]=>2
[4,2,1,1,1,1]=>1
[4,1,1,1,1,1,1]=>1
[3,3,3,1]=>3
[3,3,2,2]=>3
[3,3,2,1,1]=>3
[3,3,1,1,1,1]=>3
[3,2,2,2,1]=>2
[3,2,2,1,1,1]=>2
[3,2,1,1,1,1,1]=>1
[3,1,1,1,1,1,1,1]=>1
[2,2,2,2,2]=>2
[2,2,2,2,1,1]=>2
[2,2,2,1,1,1,1]=>2
[2,2,1,1,1,1,1,1]=>2
[2,1,1,1,1,1,1,1,1]=>1
[1,1,1,1,1,1,1,1,1,1]=>1
[5,4,2]=>0
[5,4,1,1]=>1
[5,3,3]=>3
[5,3,2,1]=>0
[5,3,1,1,1]=>1
[5,2,2,2]=>2
[5,2,2,1,1]=>2
[4,4,3]=>4
[4,4,2,1]=>4
[4,4,1,1,1]=>4
[4,3,3,1]=>3
[4,3,2,2]=>2
[4,3,2,1,1]=>1
[4,2,2,2,1]=>2
[3,3,3,2]=>3
[3,3,3,1,1]=>3
[3,3,2,2,1]=>3
[6,4,2]=>0
[5,4,3]=>0
[5,4,2,1]=>0
[5,4,1,1,1]=>1
[5,3,3,1]=>3
[5,3,2,2]=>2
[5,3,2,1,1]=>1
[5,2,2,2,1]=>2
[4,4,3,1]=>4
[4,4,2,2]=>4
[4,4,2,1,1]=>4
[4,3,3,2]=>3
[4,3,3,1,1]=>3
[4,3,2,2,1]=>2
[3,3,3,2,1]=>3
[3,3,2,2,1,1]=>3
[5,4,3,1]=>0
[5,4,2,2]=>2
[5,4,2,1,1]=>1
[5,3,3,2]=>3
[5,3,3,1,1]=>3
[5,3,2,2,1]=>2
[4,4,3,2]=>4
[4,4,3,1,1]=>4
[4,4,2,2,1]=>4
[4,3,3,2,1]=>3
[5,4,3,2]=>0
[5,4,3,1,1]=>1
[5,4,2,2,1]=>2
[5,3,3,2,1]=>3
[4,4,3,2,1]=>4
[5,4,3,2,1]=>0
                    

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Description

The largest repeated part of a partition.
If the parts of the partition are all distinct, the value of the statistic is defined to be zero.

Code

def statistic(L):
    current = -1
    for i in range(len(L)):
        prev = current
        current = L[i]
        if current == prev:
            return current
    return 0

Created

Jun 30, 2013 at 01:20 by anonymous

Updated

Dec 30, 2017 at 22:04 by Martin Rubey